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4x^2-126x+902=0
a = 4; b = -126; c = +902;
Δ = b2-4ac
Δ = -1262-4·4·902
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-38}{2*4}=\frac{88}{8} =11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+38}{2*4}=\frac{164}{8} =20+1/2 $
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